Prayas_Ages
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Question 1 of 33
1. Question
There are 2 brothers Aman and Binoy. Ratio of the ages of Aman and Binoy is 5 : x. A is 18 years younger to Chirag. After nine years Chirag will be 47 years old. If the difference between the ages of Aman and Binoy is same as the age of Chirag, what is the value of x?
CorrectIncorrect -
Question 2 of 33
2. Question
There are 2 brothers Piyush and Qureshi. The sum of present ages of Piyush and Qureshi is 11 times the difference of their ages. 5 years hence, their total ages will be 13 times the difference of their ages. What is the present age of elder one?
CorrectIncorrect -
Question 3 of 33
3. Question
Palak and Pranav, as well as their son Harsh, were 42 years old on average in a Mumbai household. Harsh married, and Amit was born to them exactly one year later. When Amit turned five years old, the family’s average age was 36. What was Palak’s age at the time of her marriage?
CorrectIncorrectHint
F+M+S=42*3=126
The age of family after 6 years =36*5=180
The age of bride after 6 years=180-(126+18+5)
=180-149==>31yrs
Age of bride at the time of marriage=31-6=25yrs. -
Question 4 of 33
4. Question
The ages of Palak, Qureshi and Ramdeva together are 57 years. Swati is thrice as old as Piyush and Ramdeva is 12 years older than Piyush. Then, the difference between ages Qureshi and Ramdeva is?
CorrectIncorrect -
Question 5 of 33
5. Question
There were two friends talking and they said that if 10 years are subtracted from the present age of Swati and the remainder is divided by 6, then the present age of his grandson Eshaan is obtained. If Eshaan is 2 years younger to Ninad whose age is 7 years, then what is Swati present age?
CorrectIncorrectHint
Eshaan age =7-2=5yrs
Let Swati age be x years. Then (x-10)/6=5
X=40 -
Question 6 of 33
6. Question
“I was as old as you are now at the time of your birth,” a father told his son. If the father is now 38 years old, the son was 5 years ago:
CorrectIncorrectHint
Let the son’s present age be x years .Then, (38 – x) = x => x= 19.
Son’s age 5 years back = (19 – 5) = 14 years -
Question 7 of 33
7. Question
In 10 years, A will be twice as old as B was 10 years ago. If A is now 9 years older than B, the present age of B is :
CorrectIncorrectHint
Let B’s present age = x years. Then, A’s present age = (x + 9) years.
(x + 9) + 10 = 2(x – 10)
=> x + 19 = 2x – 20
=> x =39. -
Question 8 of 33
8. Question
The total age of A and B is 12 years more than the total age of B and C. C is how many years younger than A ?
CorrectIncorrectHint
(A+B) – (B+C) = 12
A – C = 12.
C is younger than A by 12 years. -
Question 9 of 33
9. Question
A guy’s age is four times that of his son. The guy was nine times his son’s age when he died five years ago. What is guy’s current age?
CorrectIncorrectHint
et the son’s age be x years and the father’s age be 4x years (4x-5)=9(x-5)
5x = 40
x = 8
present age of the father = 4x = 4 x 8 = 32 years -
Question 10 of 33
10. Question
The age difference between a father and his son is 60 years. Father’s age was four times that of the son five years ago. As a result, the age of the son will now be:
CorrectIncorrectHint
Let the present ages of son and father be x and (60 -x) years respectively.
Then, (60 – x) – 5= 4(x – 5)
55 – x = 4x – 20
5x = 75 => x = 15
-
Question 11 of 33
11. Question
After 15 years, Jadhav’s age will be five times what it was five years ago. What is Jadhav’s current age?
CorrectIncorrectHint
Let Jadhav’s present age be x years.
Jadhav’s age after 15 years = (x + 15) years.
Jadhav’s age 5 years back = (x – 5) years
Then ATQ,
x + 15 = 5 (x – 5)
x + 15 = 5x – 25
=> x = 10
Hence, Jadhav’s present age = x = 10 years. -
Question 12 of 33
12. Question
“When I was as old as you are now, I was five times as old as you were,” a man told his son. If the sum of their ages is 64 years, what are their current ages?
CorrectIncorrectHint
Let the present age of the man be ‘P’ and son be ‘Q’,
Given, P + Q = 64 or Q = (64 – P)
Now the man says “I am five times as old as you were, when I was as old as you are”,
So, P = 5[B – (P – Q)]
We get 6P = 10Q,
Substitute value for Q,
6P = 10(64 – P),
Therefore P = 40, Q = 24. -
Question 13 of 33
13. Question
The current ages of two people A and B add up to 60. Find the sum of their ages 5 years from now if A’s age is twice that of B’s.
CorrectIncorrectHint
Given that, A+B = 60 and A = 2B.
Solving, We get A = 40, B = 20.
Five years their ages will be 45 and 25, so the sum of their ages will be 70. -
Question 14 of 33
14. Question
A class’s average age is 15.8 years. The average age of the boys in the class is 16.4 years old, while the average age of the girls in the class is 15.4 years old. What is the boy-to-girl ratio in the class?
CorrectIncorrectHint
Let number of boys = x , Let number of girls = y
Total numbers of students = x + y
(x + y) _ 15.8 = 16.4x + 15.4y
0.6x = 0.4y
x/y = 0.4/0.6 = 2/3
Ratio of boys and girls in the class is 2:3 -
Question 15 of 33
15. Question
A individual’s current age is one-fifth of his aunt’s. He will be half the age of his aunt after 8 years. What is the aunt’s current age?
CorrectIncorrectHint
Let the aunt’s present age be x years.
Then, the person’s present age = 2/5 x years.
(2x/5 + 8) = 1/2 (x + 8)
2(2x + 40) = 5(x + 8) => x = 40. -
Question 16 of 33
16. Question
A soccer coach is selecting a team amongst players who are aged from 20 to 35 years in integral number of years. At least how many players should be selected for the team so that, for certain, two players are of the same age?
CorrectIncorrectHint
There are 16 different ages from 20 to 35.
Therefore minimum 17 players needed -
Question 17 of 33
17. Question
The average weight of 4 men is increased by 3 kg when one of them who weighs 120 kg is replaced by another man. What is the weight of the new man?
CorrectIncorrectHint
Quicker approach: If the average is increased by 3 kg, then the sum of weighs increases by 3 _ 4 = 12 kg.
And this increase in weight is due to the extra weight included due to the inclusion of new person.
? Weight of new person = 120 + 12 = 132 kg. -
Question 18 of 33
18. Question
The average age of 8 persons in a committee is increased by 2 years when two men aged 35 yrs and 45 yrs are substituted by two women. Find the average age of these two women.q
CorrectIncorrectHint
The Total age of two women = 2 x 8 + (35+ 45)=16 + 80 = 96, Therefore, average age of two women= 96/2 = 48 yrs
-
Question 19 of 33
19. Question
In a family, a couple has a son and daughter. The age of the father is four times that of his daughter and the age of the son is half of his mother. The wife is ten years younger to her husband and the brother is six years older than his sister. What is the age of the mother?
CorrectIncorrect -
Question 20 of 33
20. Question
My brother is 3 years elder to me. My father was 28 years of age when my sister was born while my mother was 26 years of age when I was born. If my sister was 4 years of age when my brother was born, then what was the age of my father when my brother was born?
CorrectIncorrect -
Question 21 of 33
21. Question
The ratio of the ages of M and N is 6 : 5. The total of their ages is 7.7 decades. The proportion of their ages after 1.5 decades will be [1 Decade = 10 years]
CorrectIncorrect -
Question 22 of 33
22. Question
The average age of a group of 10 students is 20 years. When 5 more students join the group, the average age increase by 2 year. The average age of the new students is?
CorrectIncorrect -
Question 23 of 33
23. Question
The average age of a couple was 26 years at the time of marriage. After 11 years of marriage, the average age of the family with 3 children become 19 years. The average age of the children is
CorrectIncorrectHint
The average age of a couple = 26 years. Total age of couples = 26 x 2 = 52 years
Total age of couple after 11 years = (52 + 2 * 11 ) = 74 years If average age of 3 children after 11 years is 3x years. (74+3x)/5=19
X=7
The average age of children is 7 years. -
Question 24 of 33
24. Question
My sister was the 6th member of the family when I married ten years ago. My dad died today, and I gave birth to a child. My family’s average age during my wedding was the same as it is now. What was Father’s age when he passed away?
CorrectIncorrectHint
Let the Father be x years when he died
Average Age 10 years ago be A
Total Age 10 years ago = 6*A
Total Age after 10 years (Just before father’s Death) = 6A + 6*10 = 6A + 60
Father Died and Baby was born => the Total number of people in the family is Same (6)
Baby born today so age of baby = 0
(6A +60 – x)/6 = 6A/6
=> A + 10 -(x/6) = A
=> x/6 = 10
=> x = 60
Therefore, we can conclude that the father was 60 years old when he died. -
Question 25 of 33
25. Question
The current age of Aman’s grandson Farhan can be calculated by subtracting 6 years from his current age and dividing the remainder by 18. What is the age of Aman if Farhan is 2 years younger than Mumtaz, who is 5 years older?
CorrectIncorrectHint
Let the Present age of arun is x
Farhan age = 5-2 = 3
x-6/18 = 3
x-6 = 54
x = 60
Arun’s present age = 60 years -
Question 26 of 33
26. Question
A family of 5 people has a mean duration of 26 years. If the youngest member of the family is ten years old now, what was the average age of the family at the time of the youngest member’s birth? (Assume there hasn’t been a death in the family since the youngest was born.)
CorrectIncorrectHint
Present total age of the members = 26(5) = 130 years.
Present age of the youngest member = 10 years
Present total age of the remaining four members = 130 -10 = 120 years
Their average age at the time of the birth of the youngest member = [120?(4_10)]/4 = 30 – 10 = 20 years. -
Question 27 of 33
27. Question
Jane has been wedded for eight years. He is now 6/5 the age he was at the time of his marriage. At the time of his marriage, Jane’s sister was ten years his junior. What is Jane’s sister’s current age?
CorrectIncorrect -
Question 28 of 33
28. Question
The age difference between Mumtaz and Namdeva is 5:x. Mumtaz is 18 years Ramdeva’s junior. Ramdeva will be 47 years old in nine years. What is the value of x if the age difference between Mumtaz and Namdeva is the same as Ramdeva’s age?
CorrectIncorrectHint
Let the present ages of Mumtaz, Namdeva and Ramdeva be k, l and m respectively.
k/l = 5/x —— (1)
k = m – 18 —— (2)
m + 9 = 47 —— (3)
k – l = m —– (4)
(3) => m = 47 – 9 = 38 years
(2) => k = 38 -18 = 20 years
(1) => 20/l = 5/x => l = 4x
(4) => 4x – 20 = 38
=> 4x = 58 => x = 14.5 -
Question 29 of 33
29. Question
Ram has a family of 8 people comprising of father, mother, brother, himself and sisters. Nine years ago, the ages of the members of the family of eight people added up to 254 years. Three years later, one member died at the age of 70 years and a child was born during the same year. After another three years, one more member died, again at 80, and a child was born during the same year. The current average age of this eight-member joint family is nearest to
CorrectIncorrectHint
Nine years ago, the total age of the family is 254 years.
Six years ago, (Just before the death of the first person), the total age of the family would have been 254 + 8*3 = 254+24 = 278.
After the death of one member and the birth of a child, the total age is 208 years.
Three years ago, after the death of one member and birth of another child, the total age of the family is 208+24-80 = 152 years.
The current total age of the family is = 8_4 + 152 = 184 years
The average age is 184/8 = 23 years -
Question 30 of 33
30. Question
The ratio of the ages of Shriya and Tushar is 5 : 4. The total of their ages is 3.6 decades. The proportion of their ages after 1.2 decades will be [1 Decade = 10 years]
CorrectIncorrect -
Question 31 of 33
31. Question
One day Aman was telling Aarav that When he was married 14 years ago his wife Kamla was the 7th member of the family. Today his uncle died and his baby was born. The average age of my family during my marriage is same as today. What is the age of Uncle when he died?
CorrectIncorrectHint
Let the Uncle be x years when he died
Average Age 14 years ago be A
Total Age 14 years ago = 7*A
Total Age after 14 years (Just before uncle’s Death) = 7A + 7*14 = 7A + 98
Uncle Died and Baby was born
=> the Total number of people in the family is Same (7)
Baby born today so age of baby = (7A +98 – x)/7 = 7A/7
=> A + 14 -(x/7) = A
=> x/7 = 14
=> x = 98
Therefore we can conclude that the uncle was 98 years old when he died. -
Question 32 of 33
32. Question
Ratio of the ages of Aarav and Binoy is 7 : x. Aarav is 24 years younger to Chinoy. After 10 years Chinoy will be 55 years old. If the difference between the ages of Aarav and Binoy is same as the age of Chinoy, what is the value of x?
CorrectIncorrect -
Question 33 of 33
33. Question
When Swati was born, her niece was 40 years older than his brother and his mother was 30 years older than his sister. If Swati’s brother is 8 years older than Swati and his mother is 5 years younger than his niece, how old was Swati’s sister when Swati was born?
CorrectIncorrectHint
Swati age when he was born = 0 years
=> His brother’s age = 8 year
=> His niece’s age = brother age + 40 years = 8+40 = 48
=> His mother’s age = niece’s age – 5 = 43
So sister’s age = 43-30 = 13 years.